Mathc initiation/Fichiers c : c22cg
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c3g.c |
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/* --------------------------------- */
/* save as c3g.c */
/* --------------------------------- */
#include "x_hfile.h"
#include "fg.h"
/* --------------------------------- */
int main(void)
{
int n = 5;
double FirstApproximation = 0.5;
clrscrn();
printf(" The Newton's method : \n"
" f(x_n) \n"
" x_n+1 = x_n - ------- \n"
" f'(x_n) \n"
"\n\n\n\n\n");
printf(" Use Newton's method to approximate \n"
" the intersection point of :\n\n"
" g : x-> %s and\n"
" h : x-> %s\n\n\n"
" On a graph, you can see that, the intersection \n"
" point is between 0.0 and 1.0.\n\n"
" Choose x = %.1f as a first approximation.\n\n"
, geq, heq, FirstApproximation);
stop();
clrscrn();
printf(" In fact we want find sin(x) = cos(x) or sin(x) - cos(x) = 0\n\n"
" We want find the root of\n\n"
" f : x-> %s\n\n", feq);
printf(" As a first approximation x = %.1f \n\n",FirstApproximation);
printf(" The Newton's method give : \n\n");
p_Newton_s_Method(FirstApproximation, n, f, Df);
Newton_s_Method(FirstApproximation, n, f, Df);
printf(" f(%.15f) = %.15f\n\n",
Newton_s_Method(FirstApproximation, n, f, Df)
,f(Newton_s_Method(FirstApproximation, n, f, Df)));
stop();
return 0;
}
/* ---------------------------------- */
/* ---------------------------------- */
Fichier de commande gnuplot :
# ---------------------
# Copy and past this file into the screen of gnuplot
#
#
set zeroaxis lt 3 lw 1
plot [-2.:2.] [-1.:1.]\
cos(x),\
sin(x)
reset
# ---------------------
Nous pouvons observer que le point d'intersection est entre 0 et 1. Il faut calculer la racine de cette équation sin(x) - cos(x) = 0. On va donc choisir comme première approximation 0.5. On arrêtera les calculs lorsque l'on aura deux valeurs identiques.
Exemple de sortie écran :
The Newton's method :
f(x_n)
x_n+1 = x_n - -------
f'(x_n)
Use Newton's method to approximate
the intersection point of :
g : x-> sin(x) and
h : x-> cos(x)
On a graph, you can see that, the intersection
point is between 0.0 and 1.0.
Choose x = 0.5 as a first approximation.
Press return to continue.
************************
In fact we want find sin(x) = cos(x) or sin(x) - cos(x) = 0
We want find the root of
f : x-> sin(x) - cos(x)
As a first approximation x = 0.5
The Newton's method give :
x[1] = 0.500000000000000
x[2] = 0.793407993026023
x[3] = 0.785397992096516
x[4] = 0.785398163397448
x[5] = 0.785398163397448
f(0.785398163397448) = 0.000000000000000
Press return to continue.