« Approfondissements de lycée/Matrices » : différence entre les versions

Contenu supprimé Contenu ajouté
Ligne 295 :
 
''' Solution '''
:<math>c_{1,1} = \begin{pmatrix} 3&2 \end{pmatrix} \begin{pmatrix}2\\ 8\end{pmatrix} = (3\times 2 + 2\times 8) = (22)</math>
:<math>c_{1,2} = \begin{pmatrix} 3&2 \end{pmatrix} \begin{pmatrix}6\\ 7\end{pmatrix} = (3\times 6 + 2\times 7) = (32)</math>
:<math>c_{2,1} = \begin{pmatrix} 5&6 \end{pmatrix} \begin{pmatrix}2\\ 8\end{pmatrix} = (5\times 2 + 6\times 8) = (58)</math>
:<math>c_{2,2} = \begin{pmatrix} 5&6 \end{pmatrix} \begin{pmatrix}6\\ 7\end{pmatrix} = (5\times 6 + 6\times 7) = (72)</math>
i.e.
:<math>C =
Ligne 305 :
 
 
:<math>d_{1,1} = \begin{pmatrix} 2&6 \end{pmatrix} \begin{pmatrix}3\\ 5\end{pmatrix} = (2\times 3 + 6\times 5) = (36)</math>
:<math>d_{1,2} = \begin{pmatrix} 2&6 \end{pmatrix} \begin{pmatrix}2\\ 6\end{pmatrix} = (2\times 2 + 6\times 6) = (40)</math>
:<math>d_{2,1} = \begin{pmatrix} 8&7 \end{pmatrix} \begin{pmatrix}3\\ 5\end{pmatrix} = (8\times 3 + 7\times 5) = (59)</math>
:<math>d_{2,2} = \begin{pmatrix} 8&7 \end{pmatrix} \begin{pmatrix}2\\ 6\end{pmatrix} = (8\times 2 + 7\times 6) = (58)</math>
i.e.
:<math>D =