Mathc matrices/a194

Application

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	c00a.c

/* ------------------------------------ */
/*  Save as :   c00a.c                  */
/* ------------------------------------ */
#include "v_a.h"
/* ------------------------------------ */
int main(void)
{
int     n = 1;

double x1 = +0.50000000;
double x2 = +1.00000000;
double x3 = +0.50000000;
double x4 = +1.00000000;	
    
    do{ 
	   clrscrn();
	   printf(" Continue until integers appear : \n\n\n");	 
	         
	   printf(" n = %d -> n*x1 = %0.4f  \n",n, n*x1);	
	   printf(" n = %d -> n*x2 = %0.4f  \n",n, n*x2);	
	   printf(" n = %d -> n*x3 = %0.4f  \n",n, n*x3);		   
	   printf(" n = %d -> n*x4 = %0.4f  \n",n, n*x4);	   
	   	   
	   n++;
	   
    }while(stop_w());

    return 0;
}
/* ------------------------------------ */
/* ------------------------------------ */

• Quand n = 2

n = 2 -> n*x1 = 1.0000  
n = 2 -> n*x2 = 2.0000  
n = 2 -> n*x3 = 1.0000  
n = 2 -> n*x4 = 2.0000  

Cela nous donne les coefficients de l'équation :

$\mathrm {x_{1}CH_{4}+x_{2}O_{2}\longrightarrow x_{3}CO_{2}+x_{4}H_{2}O}$

Il suffit de remplacer les x1, x2,... par leurs valeurs numériques  :

$\mathrm {CH_{4}+2O_{2}\longrightarrow CO_{2}+2H_{2}O}$

Exemple de sortie écran :

 ---------------------
 Continue until integers appear : 


 n = 1 -> n*x1 = 0.5000  
 n = 1 -> n*x2 = 1.0000  
 n = 1 -> n*x3 = 0.5000  
 n = 1 -> n*x4 = 1.0000  

 Press   return to continue
 Press X return to stop    

 ---------------------
 Continue until integers appear : 


 n = 2 -> n*x1 = 1.0000  
 n = 2 -> n*x2 = 2.0000  
 n = 2 -> n*x3 = 1.0000  
 n = 2 -> n*x4 = 2.0000  

 Press   return to continue
 Press X return to stop