Mathc initiation/Fichiers c : c78cgb2

Sommaire

Application de cosh(x)cosh(y) 

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 Etudier:   | cosh(ax)cosh(bx) dx = 
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                                         | cosh(ax)cosh(bx) = 1/2 [cosh(ax-bx) + cosh(ax+bx)] |
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      donc  | cosh(ax)cosh(bx) dx = | 1/2 [cosh(ax-bx) + cosh(ax+bx)] dx
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                                  = 1/2 |  cosh(ax-bx) + 1/2 | cosh(ax+bx)  dx                          
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 Exemple:   | cosh(3x)cosh(2x) dx = 1/2 |  cosh(3x-2x) + 1/2 | cosh(3x+2x)  dx
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                                   = 1/2 |  cosh(x) + 1/2 | cosh(5x)  dx    
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