Mathc initiation/Fichiers c : c77di1
Calculons la primitive :
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Calculer la primitive de | sin(x)**n dx
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Utilisons l'intégration par partie
u = ... dv = ...
du = ... v = ...
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| u dv = u v - | v du
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| sin(x)**n dx =
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u = sin(x)**(n-1) dv = sin(x) dx
du = (n-1) sin(x)**(n-2) cos(x) dx v = (-cos(x))
(udv) (u*v) (v*du)
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| sin(x)**n dx = sin(x)**(n-1) * (-cos(x)) - | (-cos(x)) * (n-1) sin(x)**(n-2) cos(x) dx
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| sin(x)**n dx = - sin(x)**(n-1) * cos(x) + (n-1) | cos(x)**2 sin(x)**(n-2) dx
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cos(x)**2 = (1-sin(x)**2)
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| sin(x)**n dx = - sin(x)**(n-1) * cos(x) + (n-1) | (1-sin(x)**2) sin(x)**(n-2) dx
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| sin(x)**n dx = - sin(x)**(n-1) * cos(x) + (n-1) | (sin(x)**(n-2) - sin(x)**n) dx
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| sin(x)**n dx = - sin(x)**(n-1) * cos(x) + (n-1) | sin(x)**(n-2) dx - (n-1) | sin(x)**n dx
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| sin(x)**n dx = - sin(x)**(n-1) * cos(x) + (n-1) | sin(x)**(n-2) dx - n |sin(x)**n dx + |sin(x)**n dx
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n | sin(x)**n dx = - sin(x)**(n-1) * cos(x) + (n-1) | sin(x)**(n-2) dx
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/ 1 (n-1) /
| sin(x)**n dx = (-) -- sin(x)**(n-1) * cos(x) + ----- | sin(x)**(n-2) dx
/ n n /