Mathc initiation/Fichiers c : c61cc
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c00c.c |
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/* ---------------------------------- */
/* save as c00c.c */
/* ---------------------------------- */
#include "x_hfile.h"
#include "fc.h"
/* ---------------------------------- */
int main(void)
{
double m = IntFlux_simpson_dydz( M, N, P,
k,
u, v,LOOP,
az,bz,LOOP);
clrscrn();
printf(" Let S be the part of the graph of x = %s. \n\n", keq);
printf(" If F(x,y,z) = %si %sj %sk, find the flux of F through S\n\n\n",
Meq,Neq,Peq);
printf(" Consider k(y,z) = (%s)\n\n",keq);
printf(" n = grad(k(y,z)) / ||grad(k(y,z))||\n\n\n");
printf(" The flux of F through S is \n\n");
printf(" // \n");
printf(" || \n");
printf(" || F.n dS = %.3f\n",m);
printf(" || \n");
printf(" // \n");
printf(" S \n\n\n");
stop();
clrscrn();
printf(" Formula : \n\n");
printf(" // \n");
printf(" || \n");
printf(" || F.n dS = %.3f\n",m);
printf(" || \n");
printf(" // \n");
printf(" S \n\n\n");
printf(" //\n");
printf(" || (n)\n");
printf(" || \n");
printf(" || F . (+i-k_yj-k_zk) dS = %.3f\n",m);
printf(" || ------------ \n");
printf(" || [1+k_y**2+k_z**2]**1/2\n");
printf(" // \n");
printf(" S \n\n\n");
stop();
clrscrn();
printf(" Formula :\n\n");
printf(" //\n");
printf(" || \n");
printf(" || F . (+i-k_yj-k_zk) dS = %.3f\n",m);
printf(" || ------------ \n");
printf(" || [1+k_y**2+k_z**2]**1/2\n");
printf(" || \n");
printf(" // \n");
printf(" S \n\n\n");
printf(" //\n");
printf(" || (F) (n) (dS)\n");
printf(" || \n");
printf(" || F . (+i-k_yj-k_zk) [1+k_y**2+k_z**2]**1/2 dA = %.3f\n",m);
printf(" || ----------- \n");
printf(" || [1+k_y**2+k_z**2]**1/2\n");
printf(" // \n ");
printf(" Rxy \n\n\n");
stop();
clrscrn();
printf(" / b / v(z)\n");
printf(" | | \n");
printf(" | | F.(+i-k_yj-k_zk) [1+k_y**2+k_z**2]**1/2 dy dz = %.3f\n",m);
printf(" | | ----------- \n");
printf(" | | [1+k_y**2+k_z**2]**1/2\n");
printf(" | | \n");
printf(" / a / u(z)\n\n\n");
printf(" With.\n\n\n");
printf(" F : (x,y,z)-> %si %sj %sk \n\n",Meq,Neq,Peq);
printf(" k : (y,z)-> %s \n\n", keq);
printf(" v : (z)-> %s \n", veq);
printf(" u : (z)-> %s \n\n", ueq);
printf(" b = %+.1f\n a = %+.1f\n\n",bz,az);
stop();
return 0;
}
/* ---------------------------------- */
/* ---------------------------------- */
L'algorithme consiste à adapter la fonction qui calcule les intégrales doubles au calcul des flux.
Remarque :
Dans cette version nous utilisons cet algorithme pour l'intégrale.
/ b / v(y)
| |
| | F.(-f_xi-f_yj+k) [f_x^2+f_y^2+1]^1/2 dx dy =
| | -----------
| | [f_x^2+f_y^2+1]^1/2
| |
/ a / u(y)
Dans la prochaine version nous utiliserons la version simplifiée.
/ b / v(y)
| |
| | F.(-f_xi-f_yj+k) dx dy =
| |
/ a / u(y)
Exemple de sortie écran :
/ b / v(z)
| |
| | F.(+i-k_yj-k_zk) [1+k_y**2+k_z**2]**1/2 dy dz = 4.000
| | -----------
| | [1+k_y**2+k_z**2]**1/2
| |
/ a / u(z)
With.
F : (x,y,z)-> x+yi + zj + xzk
k : (y,z)-> 1
u : (z)-> -1
v : (z)-> +1
a = -1.0 b = +1.0
Press return to continue.